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Topic: Superfluous equalities

The task of the second class, seemed interesting, to us such for some reason did not set (and it is a pity). Underline "superfluous" equality: 7*7 - 22 = 27 4*4 - 11 = 5 8*8 - 44 = 20 29 - 2*2 = 25 6*6 - 21 = 15 8*5 - 23 = 17 Actually, it was necessary to find at first values of expressions, and then already to search for "superfluous". It is required to find one superfluous, but the teacher allows to find some "superfluous". All variants of "superfluous" equalities now are just interesting to us. Variants "in studio". P.S. I think, it is clear that such equality which possesses some property is superfluous, thus others do not possess it.

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Re: Superfluous equalities

Hello, the Corkcrew, you wrote: the Task of the second class, seemed interesting, to us such for some reason did not set (and it is a pity). Underline "superfluous" equality: 7*7 - 22 = 27 4*4 - 11 = 5 8*8 - 44 = 20 29 - 2*2 = 25 6*6 - 21 = 15 8*5 - 23 = 17 Ento - 8*5 - 23 = 17

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Re: Superfluous equalities

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Re: Superfluous equalities

Hello, CaptainFlint, you wrote: CF> 2 because the only thing is equal to a digit. CF> 3, because the only thing even. CF> 4, because multiplication to the second place, instead of on the first. CF> 6, because in product different numbers. CF> remaining to invent . Truly. In the second also the round number turns out. And here for 1 and 5 decision it is just very interesting. I to unwinding too did not invent.

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Re: Superfluous equalities

Hello, the Corkcrew, you wrote: Hello, CaptainFlint, you wrote: CF>> 2 because the only thing is equal to a digit. CF>> 3, because the only thing even. CF>> 4, because multiplication to the second place, instead of on the first. CF>> 6, because in product different numbers. CF>> remaining to invent . Truly. In the second also the round number turns out. And here for 1 and 5 decision it is just very interesting. I to unwinding too did not invent. 7*7 - 22 = 27 4*4 - 11 = 5 8*8 - 44 = 20 29 - 2*2 = 25 6*6 - 21 = 15 8*5 - 23 = 17 1 superfluous, as in the left part of an inequality the same digits, as in the right part 5 superfluous as the total of digits of the left part of an inequality is equal to the total of digits in the right part