Hello, Erop, you wrote: R>> It means, what dP = dx/L and does not depend x. E> That such dx/L FOR PAIR? R>> is not present, about a choice of a casual half it is told nothing. Consider that at first we define points, then we break. E> I from it and the beginnings, in a condition inaccurately am defined that for allocation means. A condition I formulated that is called, "on fingers", without the claim for mathematical accuracy, counting on intuitive understanding. And, to a campaign, all all is clear, to one you submit exact determination Well, I will try, specially for you. The uniform allocation of probability of a choice of points of a fracture is understood as that, at a casual choice of the next point of a fracture on segment L (not important what under the account - the first, the second, the fifth or the tenth) the probability of its hit in any section long l depends only on length of this section both is equal l/L, and does not depend from this section on a segment (in a tail, a head, or somewhere else). Presence of already selected points of a fracture does not influence in any way a choice of new points. Very much I hope that this time I managed to satisfy your severity.